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kenbol
2014-02-18T18:15:42Z
Ok, I am working on a Win 8 Box with the latest greatest VisualCron (we bought two copies yesterday). I am trying to start a python script

on cmd:

python script.py

works. The script prints "A", "B" and returns using sys.exit(0).
python.exe is in the path.

In visualcron i specify the absolute path to python (running a command). I have tried both python.exe script.py and python.exe with parameter script.py. No difference.
In all cases I get that python returns a non-zero exit code 77777. No letters are written what's so ever.

Can you please comment what's going on or what steps I should do to debug this?

Kind regards

Thomas
Sponsor
Forum information
Support
2014-02-18T19:44:58Z
You need to write full path to python.exe in command and then full path to script in argument. Use "" around argument if it contains blank spaces.
Henrik
Support
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kenbol
2014-02-19T14:11:08Z
Ok, getting closer. I can work with a local Python. I use now -V as an argument just to avoid I have problems on my side. However, I still fail to do that with a Python installed on the server. I have wasted hours already. Kind of frustrating. Is there a chance to call you?
Support
2014-02-19T14:48:43Z
Solved on phone by unchecking "local logon" on the Credential for accessing a network share where the python.exe was located on.
Henrik
Support
http://www.visualcron.com 
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